Set 5: Systems of Equations (Intermediate)

Choice D is correct. Choice D is the correct answer. Use elimination by multiplying the second equation by 3. Step 1: Multiply second equation by 3: $12x + 3 y = 57$ Step 2: Add to first equation: (2 x - 3 y) + (12 x + 3 y) = 1 + 57$14x = 58$x = \frac{58}{14} = \frac{29}{7} Non-integer. - First: $2(4) - 3(3) = 8 - 9 = -1 \neq 1$ - Second: $4(4) + 3 = 19$ ✓ Strategic Tip: Multiplying by 3 creates $+3 y$ to cancel $-3 y$. Choice A is incorrect. Choice B is incorrect because $2(5) - 3(3) = 1$ ✓, but $4(5) + 3 = 23 \neq 19$. Choice C is incorrect.