Set 4: Systems of Equations (Intermediate)

Choice C is correct. Choice C is the correct answer. Multiply first equation by 2 and second by 3 to eliminate $y$. Step 1: Multiply the equations: 8x + 6 y = 52$$15x - 6 y = 39 Step 2: Add the equations: $$$23x = 91x = \frac{91}{23}$$ Non-integer, so - First: 4(5) + 3(2) = 20 + 6 = 26$✓ - Second:$5(5) - 2(2) = 25 - 4 = 21 \neq 13$Strategic Tip: Find LCM of y-coefficients (3 and 2) which is 6. Choice A is incorrect. Choice B is incorrect. Choice D is incorrect because$4(2) + 3(6) = 26$✓, but$5(2) - 2(6) = -2 \neq 21$.