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Set 3: Systems of Equations (Intermediate)

Explanation

Answer: C

Solve the system using substitution: {x=5y2x+y=33\begin{cases} x = 5y \\ 2x + y = 33 \end{cases}

A.

(10,2)(10, 2)

B.

(20,4)(20, 4)

C.

(15,3)(15, 3)

✓ Correct
D.

(25,5)(25, 5)

Detailed Explanation

Choice C is correct. Choice C is the correct answer. Since x=5yx = 5 y is already isolated, we can directly substitute it into the second equation. Step 1: Substitute x=5yx = 5 y into 2x+y=332x + y = 33: 2(5 y) + y = 33$10y + y = 3311y = 33y = 3$$ Step 2: Find xusingusingx = 5 y: $$x = 5(3) = 15$$ Solution: (15, 3)Verification:Verification:2(15) + 3 = 30 + 3 = 33StrategicTip:Whenavariableisalreadyisolated,substitutionisthemostefficientmethod.ChoiceAisincorrectbecause✓ Strategic Tip: When a variable is already isolated, substitution is the most efficient method. Choice A is incorrect because2(10) + 2 = 20 + 2 = 22 \neq 33.ChoiceBisincorrectbecause. Choice B is incorrect because 2(20) + 4 = 40 + 4 = 44 \neq 33.ChoiceDisincorrectbecause. Choice D is incorrect because 2(25) + 5 = 50 + 5 = 55 \neq 33$.

Key Steps:

The correct answer is (15,3)(15, 3)

Why others are wrong:
A: Choice A is incorrect and may result from a calculation error.
B: Choice B is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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