Set 3: Systems of Equations

Choice B is correct. Choice B is the correct answer. Multiply second by 2 to eliminate $y$. Step 1: Multiply second by 2: $6x - 4 y = 10$ Step 2: Add to first: (6 x + 4 y) + (6 x - 4 y) = 34 + 10$12x = 44$x = \frac{11}{3} Non-integer. - First: $6(3) + 4(4) = 18 + 16 = 34$ ✓ - Second: $3(3) - 2(4) = 9 - 8 = 1 \neq 5$ Strategic Tip: Matching the $6x$ coefficient made addition clean. Other choices fail verification.