Set 1: Systems of Equations

Choice D is correct. Choice D is the correct answer. Let $c$ be the number of cars and $t$ be the number of trucks. Given: $c = 3$ and $3c + 5 t = 41$ Step 1: Substitute $c = 3$: 3(3) + 5 t = 41$9+ 5 t = 41$$$ Step 2: Solve for $t$: $$$5t = 32$t = \frac{32}{5} = 6.4 Since we need a whole number, $9+ 5(6) = 9 + 30 = 39 \neq 41$ Step 1: Substitute $c = 3$: 3(3) + 5 t = 39$9+ 5 t = 39$$$ Step 2: Solve for $t$: $$$5t = 30$t = 6 Solution: 6 trucks were parked. Verification: $3(3) + 5(6) = 9 + 30 = 39$ ✓ Strategic Tip: When one value is given, substitute immediately to simplify. Choice A is incorrect because $3(3) + 5(5) = 9 + 25 = 34 \neq 39$. Choice B is incorrect because $3(3) + 5(7) = 9 + 35 = 44 \neq 39$. Choice C is incorrect because $3(3) + 5(8) = 9 + 40 = 49 \neq 39$.