3

Set 1: Quadratic Equations

Explanation

Answer: A

What is the maximum revenue for R(p)=−4p2+400pR(p) = -4p^2 + 400p?

A.

$10,000

✓ Correct
B.

$20,000

C.

$5,000

D.

$40,000

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Substitute the optimal price (p=50p=50) back into the revenue equation. 1. R(50)=−4(50)2+400(50)R(50) = -4(50)^2 + 400(50). 2. R(50)=−4(2500)+20000R(50) = -4(2500) + 20000. 3. R(50)=−10000+20000=10000R(50) = -10000 + 20000 = 10000. Choice B is incorrect. Choice C is incorrect. Choice D is incorrect.

Key Steps:

•

The correct answer is $10,000

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.
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