Set 2: Linear Inequalities

Choice A is correct. Choice A is the correct answer. Absolute value inequalities with $<$ become compound "and" inequalities. 1. Setup: $-5 < x - 3 < 5$ 2. Add 3: $-5 + 3 < x < 5 + 3$ 3. Simplify: $-2 < x < 8$ Strategic Tip: $|A| < b$ becomes $-b < A < b$. Think "Less thAND" (Less than = And). Choice B is incorrect because it ignores the lower bound. Choice C is incorrect because it models $|x-3| > 5$ ("GreatOR" = Or). Choice D is incorrect because it solves incorrectly.