8

Set 2: Exponential Functions (Intermediate)

Explanation

Answer: C

A car purchased for $20,000 depreciates at a rate of 15% per year. Which equation models its value V(t)V(t)?

A.

V(t)=20000(0.15)tV(t) = 20000(0.15)^t

B.

V(t)=20000(1.15)tV(t) = 20000(1.15)^t

C.

V(t)=20000(0.85)tV(t) = 20000(0.85)^t

✓ Correct
D.

V(t)=2000015tV(t) = 20000 - 15t

Detailed Explanation

Choice C is correct. Choice C is the correct answer. Depreciation means decay. 1. Identify Rate: r=15%=0.15r = 15\% = 0.15. 2. Calculate Factor: b=1r=10.15=0.85b = 1 - r = 1 - 0.15 = 0.85. 3. Form Equation: V(t)=20000(0.85)tV(t) = 20000(0.85)^t. Strategic Tip: For depreciation, the base must be less than 1. Choice A is incorrect because 0.15 would mean losing 85% per year. Choice B is incorrect because 1.15 means the car gains value. Choice D is incorrect because it represents linear depreciation.

Key Steps:

The correct answer is V(t)=20000(0.85)tV(t) = 20000(0.85)^t

Why others are wrong:
A: Choice A is incorrect and may result from a calculation error.
B: Choice B is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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