10

Set 4: Exponential Functions

Explanation

Answer: A

If 2x=3y2^x = 3^y and x=6x = 6, what is yy?

A.

y=6ln(2)ln(3)y = \frac{6\ln(2)}{\ln(3)}

✓ Correct
B.

y=6y = 6

C.

y=6ln(3)ln(2)y = \frac{6\ln(3)}{\ln(2)}

D.

y=4y = 4

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Use logarithms to solve for yy. 1. Given: 26=3y2^6 = 3^y, so 64=3y64= 3^y. 2. Take natural log: ln(64)=ln(3y)=yln(3)\ln(64) = \ln(3^y) = y\ln(3). 3. Solve: y=ln(64)ln(3)=ln(26)ln(3)=6ln(2)ln(3)y = \frac{\ln(64)}{\ln(3)} = \frac{\ln(2^6)}{\ln(3)} = \frac{6\ln(2)}{\ln(3)}. 4. Numerical: y6(0.693)1.0993.79y \approx \frac{6(0.693)}{1.099} \approx 3.79. Strategic Tip: To solve ax=ba^x = b, use x=ln(b)ln(a)x = \frac{\ln(b)}{\ln(a)}. Choice B is incorrect because 36=729643^6 = 729 \neq 64. Choice C is incorrect because this inverts the logarithms. Choice D is incorrect because 34=81643^4 = 81 \neq 64.

Key Steps:

The correct answer is y=6ln(2)ln(3)y = \frac{6\ln(2)}{\ln(3)}

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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