Set 16: Systems of Equations

Choice B is correct. Choice B is the correct answer. Let $m$ = monkeys and $p$ = parrots. System: $\begin{cases} m + p = 28 \\ 4 m + 2 p = 76 \end{cases}$ Step 1: From first: $p = 28 - m$ Step 2: Substitute: $$$4m + 2(28 - m) = 76$4m + 56 - 2 m = 76$2m = 20m = 10$$ Solution: 10 monkeys Verification: $$10+ 18 = 28$$ ✓ and 4(10) + 2(18) = 40 + 36 = 76$ ✓ Strategic Tip: Count heads for one equation, legs for the other.