Set 14: Systems of Equations (Intermediate)

Choice D is correct. Choice D is the correct answer. Multiply first by 2 and second by 5. Step 1: Multiply: 8x + 10 y = 66$$15x - 10 y = 40 Step 2: Add: $$$23x = 106x = \frac{106}{23}$$ Non-integer. - First: 4(4) + 5(\frac{17}{5}) = 16 + 17 = 33$✓ - Second:$3(4) - 2(\frac{17}{5}) = 12 - \frac{34}{5} = \frac{60-34}{5} = \frac{26}{5} \neq 8$ Strategic Tip: LCM of 5 and 2 is 10. Other choices fail.