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Set 14: Systems of Equations (Intermediate)

Explanation

Answer: B

A store sells nuts in bulk. Cashews cost $12 per pound and peanuts cost $6 per pound. How many pounds of peanuts should be mixed with 10 pounds of cashews to make a mixture worth $9 per pound?

A.

8 pounds

B.

10 pounds

✓ Correct
C.

12 pounds

D.

15 pounds

Detailed Explanation

Choice B is correct. Choice B is the correct answer. Let pp = pounds of peanuts. Step 1: Set up the equation: 12(10)+6p10+p=9\frac{12(10) + 6 p}{10 + p} = 9 The numerator is total value, denominator is total weight. Step 2: Multiply both sides by (10+p)(10 + p): $$$120+ 6 p = 9(10 + p)120+6p=90+9p120+ 6 p = 90 + 9 p120- 90 = 9 p - 6 p30= 3 p$p = 10 Solution: 10 pounds of peanuts Verification: - Total value: 12(10)+6(10)=120+60=18012(10) + 6(10) = 120 + 60 = 180 - Total weight: 10+10=2010+ 10 = 20 - Price per pound: 18020=9\frac{180}{20} = 9 ✓ Strategic Tip: Mixture problems: (sum of values) ÷ (sum of quantities) = average price. Choice A is incorrect because 120+4818=168189.339\frac{120 + 48}{18} = \frac{168}{18} \approx 9.33 \neq 9. Choice C is incorrect because 120+7222=192228.739\frac{120 + 72}{22} = \frac{192}{22} \approx 8.73 \neq 9. Choice D is incorrect because 120+9025=21025=8.49\frac{120 + 90}{25} = \frac{210}{25} = 8.4 \neq 9.

Key Steps:

The correct answer is 10 pounds

Why others are wrong:
A: Choice A is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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