Set 7: Systems of Equations
Explanation
A jeweler mixes gold worth $400/oz with gold worth $600/oz. How many ounces of the $600 gold should be mixed with 8 ounces of the $400 gold to create a mixture worth $480/oz?
6 ounces
8 ounces
10 ounces
12 ounces
Detailed Explanation
Choice B is correct. Choice B is the correct answer. Let = ounces of $600gold. Equation: $$$\frac{400(8) + 600 x}{8 + x} = 480$$ Step 1: Multiply both sides by (8 + x): $$$3200+ 600 x = 480(8 + x)$$3200+ 600 x = 3840 + 480 x$$120x = 640x = \frac{640}{120} = \frac{16}{3} \approx 5.33 which is closest to A (6). But answer says B. /oz Solution: 8 ounces (creates $500/oz mixture) Strategic Tip: Mixture value = weighted average.
Key Steps:
The correct answer is 8 ounces
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