9

Set 9: Exponential Functions (Intermediate)

Explanation

Answer: B

If 52x=255x5^{2x} = 25 \cdot 5^x, what is xx?

A.

x=0x = 0

B.

x=2x = 2

✓ Correct
C.

x=1x = 1

D.

x=1x = -1

Detailed Explanation

Choice B is correct. Choice B is the correct answer. Rewrite with the same base and solve. 1. Rewrite: 25=5225= 5^2, so 255x=525x=5x+225\cdot 5^x = 5^2 \cdot 5^x = 5^{x+2}. 2. Equation: 52x=5x+25^{2 x} = 5^{x+2}. 3. Equal bases: Set exponents equal: 2x=x+22x = x + 2. 4. Solve: 2xx=22x - x = 2, so x=2x = 2. 5. Verify: 52(2)=54=6255^{2(2)} = 5^4 = 625 and 2552=2525=62525\cdot 5^2 = 25 \cdot 25 = 625 ✓ Strategic Tip: When bases are equal, set exponents equal to solve. Choice A is incorrect because 50=15^0 = 1 and 2550=2525\cdot 5^0 = 25, not equal. Choice C is incorrect because 52=255^2 = 25 and 255=12525\cdot 5 = 125, not equal. Choice D is incorrect because 52=0.045^{-2} = 0.04 and 2551=525\cdot 5^{-1} = 5, not equal.

Key Steps:

The correct answer is x=2x = 2

Why others are wrong:
A: Choice A is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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