10

Set 9: Exponential Functions (Intermediate)

Explanation

Answer: A

A virus spreads according to I(t)=100001+9999e1.5tI(t) = \frac{10000}{1 + 9999e^{-1.5t}} where tt is days. How long until 5,000 people are infected?

A.

About 6.1 days

✓ Correct
B.

About 10 days

C.

About 3 days

D.

About 15 days

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Solve for tt when I(t)=5000I(t) = 5000. 1. Equation: 5000=100001+9999e1.5t5000= \frac{10000}{1 + 9999 e^{-1.5 t}}. 2. Multiply: 5000(1+9999e1.5t)=100005000(1 + 9999 e^{-1.5 t}) = 10000. 3. Simplify: 1+9999e1.5t=21+ 9999 e^{-1.5 t} = 2. 4. Isolate: 9999e1.5t=19999e^{-1.5 t} = 1, so e1.5t=19999e^{-1.5 t} = \frac{1}{9999}. 5. Natural log: 1.5t=ln(19999)=ln(9999)9.21-1.5 t = \ln(\frac{1}{9999}) = -\ln(9999) \approx -9.21. 6. Solve: t=9.211.56.146.1t = \frac{9.21}{1.5} \approx 6.14 \approx 6.1 days. Strategic Tip: In logistic models, half of carrying capacity occurs when Aert=1Ae^{-rt} = 1. Choice B is incorrect because this is too long. Choice C is incorrect because this is too short. Choice D is incorrect because this is way too long.

Key Steps:

The correct answer is About 6.1 days

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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