3

Set 10: Exponential Functions (Intermediate)

Explanation

Answer: A

Carbon-14 has a half-life of 5,730 years. If a fossil has 25% of its original carbon-14, approximately how old is it?

A.

11,460 years

✓ Correct
B.

5,730 years

C.

17,190 years

D.

2,865 years

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Work backwards from the remaining percentage. 1. Remaining: 25% = 14\frac{1}{4} of original. 2. Half-lives: 14=(12)2\frac{1}{4} = (\frac{1}{2})^2, so 2 half-lives have passed. 3. Time: 2×5730=11,4602\times 5730 = 11,460 years. 4. Formula: 0.25=(0.5)t/57300.25= (0.5)^{t/5730}, solving gives t=11,460t = 11,460. Strategic Tip: 25% = 14\frac{1}{4} = 2 half-lives have occurred. Choice B is incorrect because this is only 1 half-life (50% remaining). Choice C is incorrect because this is 3 half-lives (12.5% remaining). Choice D is incorrect because this is half of one half-life.

Key Steps:

The correct answer is 11,460 years

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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