9
algebra

A solution is 15% alcohol. How much pure alcohol must be added to 60 liters to increase the concentration to 25% alcohol?

A

6 liters

B

8 liters

C

10 liters

D

12 liters

Correct Answer: B

Choice B is the correct answer. Let xx = liters of pure alcohol (100%) to add.

Equation: Amount of alcohol before = amount after 0.15(60)+1.00(x)=0.25(60+x)0.15(60) + 1.00(x) = 0.25(60 + x)9+x=15+0.25x9 + x = 15 + 0.25x0.75x=60.75x = 6x=8x = 8

Solution: 8 liters of pure alcohol

Verification: 9+860+8=1768=0.25=25%\frac{9 + 8}{60 + 8} = \frac{17}{68} = 0.25 = 25\%

💡 Strategic Tip: Pure substance = 100% concentration.

**Other choices fail verification.