9
algebra

A solution is 30% acid. How much pure water must be added to 40 liters of this solution to dilute it to 24% acid?

A

8 liters

B

10 liters

C

12 liters

D

15 liters

Correct Answer: B

Choice B is the correct answer. Let ww = liters of water to add.

Equation: Amount of acid stays the same 0.30(40)=0.24(40+w)0.30(40) = 0.24(40 + w)12=9.6+0.24w12 = 9.6 + 0.24w2.4=0.24w2.4 = 0.24ww=10w = 10

** **Other choices fail verification.

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Linear Functions Set 58