5
algebra

A concert venue has two types of seats. Floor seats cost $75 and balcony seats cost $45. The venue sold out all 400 seats for $22,500. How many floor seats were sold?

A

100 floor seats

B

125 floor seats

C

150 floor seats

D

175 floor seats

Correct Answer: C

Choice C is the correct answer. Let ff = floor seats and bb = balcony seats.

System: {f+b=40075f+45b=22500\begin{cases} f + b = 400 \\ 75f + 45b = 22500 \end{cases}

Step 1: From first: b=400fb = 400 - f

Step 2: Substitute: 75f+45(400f)=2250075f + 45(400 - f) = 2250075f+1800045f=2250075f + 18000 - 45f = 2250030f=450030f = 4500f=150f = 150

Solution: 150 floor seats (and 250 balcony seats)

Verification: 150+250=400150 + 250 = 400 ✓ and 75(150)+45(250)=11250+11250=2250075(150) + 45(250) = 11250 + 11250 = 22500

💡 Strategic Tip: Revenue problems: quantity × price = total revenue.

Choice A is incorrect because 75(100)+45(300)=7500+13500=21000 eq2250075(100) + 45(300) = 7500 + 13500 = 21000 \ eq 22500.

Choice B is incorrect because 75(125)+45(275)=9375+12375=21750 eq2250075(125) + 45(275) = 9375 + 12375 = 21750 \ eq 22500.

Choice D is incorrect because 75(175)+45(225)=13125+10125=23250 eq2250075(175) + 45(225) = 13125 + 10125 = 23250 \ eq 22500.