Choice C is the correct answer. Let $m$ = motorcycles and $c$ = cars.

System: $\begin{cases} m + c = 35 \\ 2m + 4c = 110 \end{cases}$

Step 1: From first equation: $m = 35 - c$

Step 2: Substitute: $2(35 - c) + 4c = 110$$70 - 2c + 4c = 110$$2c = 40$$c = 20$

Step 3: Find $m$: $m = 35 - 20 = 15$

• 15 motorcycles + 20 cars = 35 vehicles ✓

• Wheels: $2(15) + 4(20) = 30 + 80 = 110$ ✓

• 10 motorcycles + 25 cars = 35 vehicles ✓

• Wheels: $2(10) + 4(25) = 20 + 100 = 120 \ eq 110$

💡 Strategic Tip: Count vehicles for one equation, wheels for another.

Choice A is incorrect because $2(15) + 4(20) = 30 + 80 = 110 \ eq 120$.

Choice B is incorrect because $2(20) + 4(15) = 40 + 60 = 100 \ eq 120$.

Choice D is incorrect because $2(25) + 4(10) = 50 + 40 = 90 \ eq 120$.