9
algebra

A store sells nuts in bulk. Cashews cost $12 per pound and peanuts cost $6 per pound. How many pounds of peanuts should be mixed with 10 pounds of cashews to make a mixture worth $9 per pound?

A

8 pounds

B

10 pounds

C

12 pounds

D

15 pounds

Correct Answer: B

Choice B is the correct answer. Let pp = pounds of peanuts.

Step 1: Set up the equation: 12(10)+6p10+p=9\frac{12(10) + 6p}{10 + p} = 9

The numerator is total value, denominator is total weight.

Step 2: Multiply both sides by (10+p)(10 + p): 120+6p=9(10+p)120 + 6p = 9(10 + p)120+6p=90+9p120 + 6p = 90 + 9p12090=9p6p120 - 90 = 9p - 6p30=3p30 = 3pp=10p = 10

Solution: 10 pounds of peanuts

Verification:

  • Total value: 12(10)+6(10)=120+60=18012(10) + 6(10) = 120 + 60 = 180
  • Total weight: 10+10=2010 + 10 = 20
  • Price per pound: 18020=9\frac{180}{20} = 9

💡 Strategic Tip: Mixture problems: (sum of values) ÷ (sum of quantities) = average price.

Choice A is incorrect because 120+4818=168189.33 eq9\frac{120 + 48}{18} = \frac{168}{18} \approx 9.33 \ eq 9.

Choice C is incorrect because 120+7222=192228.73 eq9\frac{120 + 72}{22} = \frac{192}{22} \approx 8.73 \ eq 9.

Choice D is incorrect because 120+9025=21025=8.4 eq9\frac{120 + 90}{25} = \frac{210}{25} = 8.4 \ eq 9.