1
algebra

A coffee shop sells small coffees for $3 and large coffees for $5. One day, they sold 80 coffees total and earned $340. How many small coffees were sold?

A

30 small coffees

B

40 small coffees

C

50 small coffees

D

20 small coffees

Correct Answer: A

Choice A is the correct answer. Let ss = small coffees and LL = large coffees.

Step 1: Set up the system: {s+L=803s+5L=340\begin{cases} s + L = 80 \\ 3s + 5L = 340 \end{cases}

Step 2: From the first equation: L=80sL = 80 - s

Step 3: Substitute into the second equation: 3s+5(80s)=3403s + 5(80 - s) = 3403s+4005s=3403s + 400 - 5s = 3402s=60-2s = -60s=30s = 30

Solution: 30 small coffees (and 50 large coffees)

Verification: 30+50=8030 + 50 = 80 ✓ and 3(30)+5(50)=90+250=3403(30) + 5(50) = 90 + 250 = 340

💡 Strategic Tip: In mixture/combination problems, one equation represents quantity, the other represents value.

Choice B is incorrect because 3(40)+5(40)=320 eq3403(40) + 5(40) = 320 \ eq 340.

Choice C is incorrect because 3(50)+5(30)=300 eq3403(50) + 5(30) = 300 \ eq 340.

Choice D is incorrect because 3(20)+5(60)=360 eq3403(20) + 5(60) = 360 \ eq 340.