4
algebra

Which value makes the system have infinitely many solutions? {8x12y=202x3y=k\begin{cases} 8x - 12y = 20 \\ 2x - 3y = k \end{cases}

A

k=20k = 20

B

k=8k = 8

C

k=5k = 5

D

k=10k = 10

Correct Answer: C

Choice C is the correct answer. For infinitely many solutions, the equations must be multiples of each other.

Step 1: Notice the first equation's coefficients are 4 times the second's: 8x12y=4(2x3y)8x - 12y = 4(2x - 3y)

Step 2: Divide the first equation by 4: 8x12y4=204\frac{8x - 12y}{4} = \frac{20}{4}2x3y=52x - 3y = 5

Verification: With k=5k = 5, multiply second by 4: 4(2x3y)=4(5)=204(2x - 3y) = 4(5) = 208x12y=208x - 12y = 20 ✓ (matches first equation)

💡 Strategic Tip: If coefficients are scaled by factor nn, the constant must also be scaled by nn.

Choice A is incorrect because k=20k = 20 would give parallel lines (no solution).

Choice B is incorrect because k=8k = 8 would give parallel lines.

Choice D is incorrect because k=10k = 10 would give parallel lines.