2
algebra

For what value of aa does the system have infinitely many solutions? {5x2y=1010x4y=a\begin{cases} 5x - 2y = 10 \\ 10x - 4y = a \end{cases}

A

a=10a = 10

B

a=5a = 5

C

a=20a = 20

D

a=40a = 40

Correct Answer: C

Choice C is the correct answer. For infinitely many solutions, the second equation must be a multiple of the first.

Step 1: Notice that the coefficients in the second equation are exactly double those in the first:

  • First: 5x2y=105x - 2y = 10
  • Second: 10x4y=a10x - 4y = a

Step 2: Multiply the first equation by 2: 2(5x2y)=2(10)2(5x - 2y) = 2(10)10x4y=2010x - 4y = 20

Verification: With a=20a = 20, the second equation is exactly double the first, 💡 Strategic Tip: When coefficients are scaled by a factor, the constant must be scaled by the same factor.

Choice A is incorrect because a=10a = 10 would give parallel lines (no solution).

Choice B is incorrect because a=5a = 5 would give parallel lines.

Choice D is incorrect because a=40a = 40 would give parallel lines.