Choice C is the correct answer. Let's check if one equation is a multiple of the other.

Step 1: Divide the first equation by 3: $\frac{6x - 3y}{3} = \frac{12}{3}$$2x - y = 4$

This is exactly the second equation!

Step 2: Since both equations represent the same line, every point on that line satisfies both equations.

Conclusion: Infinitely many solutions

💡 Strategic Tip: When equations are scalar multiples of each other (including the constant), they represent the same line.

Choice A is incorrect because one solution requires different slopes.

Choice B is incorrect because no solution requires parallel lines with different constants.

Choice D is incorrect because we can always determine this by simplifying.