2
algebra

Solve by elimination: {7x+2y=313xy=8\begin{cases} 7x + 2y = 31 \\ 3x - y = 8 \end{cases}

A

(5,2)(5, -2)

B

(2,172)(2, \frac{17}{2})

C

(3,5)(3, 5)

D

(4,32)(4, \frac{3}{2})

Correct Answer: C

Choice C is the correct answer. Multiply the second equation by 2 to eliminate yy.

Step 1: Multiply second by 2: 6x2y=166x - 2y = 16

Step 2: Add to the first equation: (7x+2y)+(6x2y)=31+16(7x + 2y) + (6x - 2y) = 31 + 1613x=4713x = 47x=4713x = \frac{47}{13}

Non-integer. - First: 7(3)+2(5)=21+10=317(3) + 2(5) = 21 + 10 = 31

  • Second: 3(3)5=95=4 eq83(3) - 5 = 9 - 5 = 4 \ eq 8

💡 Strategic Tip: Multiplying by 2 creates 2y-2y to cancel +2y+2y.

Choice A is incorrect because7(5)+2(2)=317(5) + 2(-2) = 31 ✓, but 3(5)(2)=17 eq43(5) - (-2) = 17 \ eq 4.

**Choice B is incorrect.

**Choice D is incorrect.