1
algebra

Solve using substitution: {2x+y=153x4y=6\begin{cases} 2x + y = 15 \\ 3x - 4y = 6 \end{cases}

A

(6,3)(6, 3)

B

(4,7)(4, 7)

C

(5,5)(5, 5)

D

(7,1)(7, 1)

Correct Answer: A

Choice A is the correct answer. Isolate yy from the first equation.

Step 1: From 2x+y=152x + y = 15: y=152xy = 15 - 2x

Step 2: Substitute into the second equation: 3x4(152x)=63x - 4(15 - 2x) = 63x60+8x=63x - 60 + 8x = 611x=6611x = 66x=6x = 6

Step 3: Find yy: y=152(6)=3y = 15 - 2(6) = 3

Solution: (6,3)(6, 3)

Verification: 3(6)4(3)=1812=63(6) - 4(3) = 18 - 12 = 6

💡 Strategic Tip: Isolating yy was natural since its coefficient in the first equation is 1.

Choice B is incorrect because3(4)4(7)=1228=16 eq63(4) - 4(7) = 12 - 28 = -16 \ eq 6.

Choice C is incorrect because3(5)4(5)=1520=5 eq63(5) - 4(5) = 15 - 20 = -5 \ eq 6.

Choice D is incorrect because3(7)4(1)=214=17 eq63(7) - 4(1) = 21 - 4 = 17 \ eq 6.