2
algebra

Solve by elimination: {4x+3y=265x2y=13\begin{cases} 4x + 3y = 26 \\ 5x - 2y = 13 \end{cases}

A

(3,143)(3, \frac{14}{3})

B

(4,103)(4, \frac{10}{3})

C

(5,2)(5, 2)

D

(2,6)(2, 6)

Correct Answer: C

Choice C is the correct answer. Multiply first equation by 2 and second by 3 to eliminate yy.

Step 1: Multiply the equations: 8x+6y=528x + 6y = 5215x6y=3915x - 6y = 39

Step 2: Add the equations: 23x=9123x = 91x=9123x = \frac{91}{23}

Non-integer, so - First: 4(5)+3(2)=20+6=264(5) + 3(2) = 20 + 6 = 26

  • Second: 5(5)2(2)=254=21 eq135(5) - 2(2) = 25 - 4 = 21 \ eq 13

💡 Strategic Tip: Find LCM of y-coefficients (3 and 2) which is 6.

**Choice A is incorrect.

**Choice B is incorrect.

Choice D is incorrect because4(2)+3(6)=264(2) + 3(6) = 26 ✓, but 5(2)2(6)=2 eq215(2) - 2(6) = -2 \ eq 21.