1
algebra

Solve using substitution: {x+4y=223x2y=10\begin{cases} x + 4y = 22 \\ 3x - 2y = 10 \end{cases}

A

(8,3.5)(8, 3.5)

B

(6,4)(6, 4)

C

(5,4.25)(5, 4.25)

D

(7,3.75)(7, 3.75)

Correct Answer: B

Choice B is the correct answer. Isolate xx from the first equation.

Step 1: From x+4y=22x + 4y = 22: x=224yx = 22 - 4y

Step 2: Substitute into the second equation: 3(224y)2y=103(22 - 4y) - 2y = 106612y2y=1066 - 12y - 2y = 106614y=1066 - 14y = 1014y=56-14y = -56y=4y = 4

Step 3: Find xx: x=224(4)=2216=6x = 22 - 4(4) = 22 - 16 = 6

Solution: (6,4)(6, 4)

Verification: 3(6)2(4)=188=103(6) - 2(4) = 18 - 8 = 10

💡 Strategic Tip: Isolating xx was easier here since its coefficient is 1 in the first equation.

Choice A is incorrect because3(8)2(3.5)=247=17 eq103(8) - 2(3.5) = 24 - 7 = 17 \ eq 10.

Choice C is incorrect because3(5)2(4.25)=158.5=6.5 eq103(5) - 2(4.25) = 15 - 8.5 = 6.5 \ eq 10.

Choice D is incorrect because3(7)2(3.75)=217.5=13.5 eq103(7) - 2(3.75) = 21 - 7.5 = 13.5 \ eq 10.