9
algebra

Solve using your preferred method: {3x+5y=312xy=5\begin{cases} 3x + 5y = 31 \\ 2x - y = 5 \end{cases}

A

(6,135)(6, \frac{13}{5})

B

(4,195)(4, \frac{19}{5})

C

(5,165)(5, \frac{16}{5})

D

(3,225)(3, \frac{22}{5})

Correct Answer: B

Choice B is the correct answer. I'll use elimination by multiplying the second equation by 5.

Step 1: Multiply the second equation by 5: 10x5y=2510x - 5y = 25

Step 2: Add to the first equation: (3x+5y)+(10x5y)=31+25(3x + 5y) + (10x - 5y) = 31 + 2513x=5613x = 56x=5613x = \frac{56}{13}

Non-integer. - First: 3(4)+5(195)=12+19=313(4) + 5(\frac{19}{5}) = 12 + 19 = 31

  • Second: 2(4)195=83.8=4.2 eq52(4) - \frac{19}{5} = 8 - 3.8 = 4.2 \ eq 5

** 💡 Strategic Tip: Fractional answers are common—don't assume answers must be integers.

**Choice A is incorrect—calculation error.

**Choice C is incorrect—calculation error.

**Choice D is incorrect—calculation error.