Choice C is the correct answer. We'll multiply to eliminate $y$: first equation by 3, second by 4.

Step 1: Multiply the equations: $15x + 12y = 99$$8x - 12y = 4$

Step 2: Add: $23x = 103$$x = \frac{103}{23}$

Non-integer. - First: $5(5) + 4(2) = 25 + 8 = 33$ ✓

• Second: $2(5) - 3(2) = 10 - 6 = 4 \ eq 1$

Step 1: Multiply: $15x + 12y = 99$$8x - 12y = 16$

Step 2: Add: $23x = 115$$x = 5$

Step 3: Substitute: $5(5) + 4y = 33$$25 + 4y = 33$$y = 2$

** 💡 Strategic Tip: The LCM of 4 and 3 is 12, so we multiply to get $12y$ and $-12y$.

Choice A is incorrect because$5(6) + 4(0.75) = 33$ ✓, but $2(6) - 3(0.75) \ eq 4$.

Choice B is incorrect because$5(4) + 4(\frac{13}{4}) = 20 + 13 = 33$ ✓, but $2(4) - 3(\frac{13}{4}) \ eq 4$.

Choice D is incorrect because$5(3) + 4(4.5) = 15 + 18 = 33$ ✓, but $2(3) - 3(4.5) = -7.5 \ eq 4$.