Choice B is the correct answer. I'll use elimination by multiplying the second equation by 3.

Step 1: Multiply the second equation by 3: $6x - 3y = 9$

Step 2: Add to the first equation: $(x + 3y) + (6x - 3y) = 13 + 9$$7x = 22$$x = \frac{22}{7}$

Non-integer. - First: $4 + 3(3) = 4 + 9 = 13$ ✓

• Second: $2(4) - 3 = 8 - 3 = 5 \ eq 3$

Step 1: Multiply second by 3: $6x - 3y = 15$

Step 2: Add: $7x = 28$$x = 4$

Step 3: Substitute: $4 + 3y = 13$$y = 3$

Solution: $(4, 3)$

Verification: $x + 3y = 13$ ✓ and $2x - y = 5$ ✓

💡 Strategic Tip: With coefficient 1 on x, either substitution or elimination works well.

Choice A is incorrect because$2 + 3(\frac{11}{3}) = 13$ ✓, but $2(2) - \frac{11}{3} \ eq 5$.

Choice C is incorrect because$5 + 3(\frac{8}{3}) = 13$ ✓, but $2(5) - \frac{8}{3} \ eq 5$.

Choice D is incorrect because$1 + 3(4) = 13$ ✓, but $2(1) - 4 = -2 \ eq 5$.