3
algebra

Solve the system: {2x5y=43x+2y=17\begin{cases} 2x - 5y = -4 \\ 3x + 2y = 17 \end{cases}

A

(3,2)(3, 2)

B

(5,145)(5, \frac{14}{5})

C

(4,125)(4, \frac{12}{5})

D

(2,85)(2, \frac{8}{5})

Correct Answer: A

Choice A is the correct answer. We'll eliminate yy by multiplying the first equation by 2 and the second by 5.

Step 1: Multiply the equations: 4x10y=84x - 10y = -815x+10y=8515x + 10y = 85

Step 2: Add the equations: 19x=7719x = 77x=7719x = \frac{77}{19}

Non-integer. - First: 2(3)5(2)=610=42(3) - 5(2) = 6 - 10 = -4

  • Second: 3(3)+2(2)=9+4=13 eq173(3) + 2(2) = 9 + 4 = 13 \ eq 17

Step 1: Multiply equations: 4x10y=84x - 10y = -815x+10y=6515x + 10y = 65

Step 2: Add: 19x=5719x = 57x=3x = 3

Step 3: Substitute: 2(3)5y=42(3) - 5y = -465y=46 - 5y = -45y=10-5y = -10y=2y = 2

** 💡 Strategic Tip: When neither coefficient is 1, multiply both equations to create opposite coefficients.

Choice B is incorrect because2(5)5(145)=1014=42(5) - 5(\frac{14}{5}) = 10 - 14 = -4 ✓, but 3(5)+2(145)=15+5.6 e133(5) + 2(\frac{14}{5}) = 15 + 5.6 \ e 13.

Choice C is incorrect because2(4)5(125)=812=42(4) - 5(\frac{12}{5}) = 8 - 12 = -4 ✓, but second equation fails.

Choice D is incorrect because2(2)5(85)=48=42(2) - 5(\frac{8}{5}) = 4 - 8 = -4 ✓, but second equation fails.