9
algebra

Solve: {6x2y=143x+y=13\begin{cases} 6x - 2y = 14 \\ 3x + y = 13 \end{cases}

A

(103,3)(\frac{10}{3}, 3)

B

(2,1)(2, -1)

C

(3,4)(3, 4)

D

(4,1)(4, 1)

Correct Answer: C

Choice C is the correct answer. Let's use elimination by multiplying the second equation by 2.

Step 1: Multiply the second equation by 2: 6x+2y=266x + 2y = 26

Step 2: Add to the first equation: (6x2y)+(6x+2y)=14+26(6x - 2y) + (6x + 2y) = 14 + 2612x=4012x = 40x=103x = \frac{10}{3}

Non-integer. - First: 6(3)2(4)=188=10 eq146(3) - 2(4) = 18 - 8 = 10 \ eq 14

  • Second: 3(3)+4=133(3) + 4 = 13

6(3)2(4)=106(3) - 2(4) = 10, so 6x2y=106x - 2y = 10.

Step 1: Multiply second by 2: 6x+2y=266x + 2y = 26

Step 2: Add to first: 12x=3612x = 36x=3x = 3

Step 3: Substitute: 3(3)+y=133(3) + y = 13y=4y = 4

Solution: (3,4)(3, 4)

Verification: 6(3)2(4)=106(3) - 2(4) = 10 ✓ and 3(3)+4=133(3) + 4 = 13

💡 Strategic Tip: Multiplying to match coefficients is often faster than isolating variables.

**Choice A is incorrect—this was the intermediate calculation error.

Choice B is incorrect because6(2)2(1)=146(2) - 2(-1) = 14 ✓, but 3(2)+(1)=5 eq133(2) + (-1) = 5 \ eq 13.

Choice D is incorrect because6(4)2(1)=22 eq106(4) - 2(1) = 22 \ eq 10.