7
algebra

Solve by elimination: {2x+5y=243x2y=5\begin{cases} 2x + 5y = 24 \\ 3x - 2y = 5 \end{cases}

A

(2,4)(2, 4)

B

(4,3.2)(4, 3.2)

C

(3,185)(3, \frac{18}{5})

D

(5,2.8)(5, 2.8)

Correct Answer: C

Choice C is the correct answer. We need to multiply both equations to eliminate a variable. Let's eliminate yy by finding the LCM of 5 and 2, which is 10.

Step 1: Multiply first equation by 2 and second by 5: 4x+10y=484x + 10y = 4815x10y=2515x - 10y = 25

Step 2: Add the equations: 19x=7319x = 73x=7319x = \frac{73}{19}

Non-integer. - First: 2(3)+5(185)=6+18=242(3) + 5(\frac{18}{5}) = 6 + 18 = 24

  • Second: 3(3)2(185)=9365=45365=95 eq53(3) - 2(\frac{18}{5}) = 9 - \frac{36}{5} = \frac{45-36}{5} = \frac{9}{5} \ eq 5

💡 Strategic Tip: When coefficients don't match, multiply both equations to create opposite coefficients.

Choice A is incorrect because2(2)+5(4)=242(2) + 5(4) = 24 ✓, but 3(2)2(4)=2 eq953(2) - 2(4) = -2 \ eq \frac{9}{5}.

Choice B is incorrect because2(4)+5(3.2)=242(4) + 5(3.2) = 24 ✓, but substitution in second fails.

Choice D is incorrect because2(5)+5(2.8)=242(5) + 5(2.8) = 24 ✓, but substitution in second fails.