6
algebra

Solve by substitution: {3x4y=10x+2y=8\begin{cases} 3x - 4y = 10 \\ x + 2y = 8 \end{cases}

A

(6,1)(6, 1)

B

(4,12)(4, \frac{1}{2})

C

(2,3)(2, 3)

D

(8,0)(8, 0)

Correct Answer: A

Choice A is the correct answer. Let's isolate xx from the second equation since it has coefficient 1.

Step 1: Isolate xx in the second equation: x=82yx = 8 - 2y

Step 2: Substitute into the first equation: 3(82y)4y=103(8 - 2y) - 4y = 10246y4y=1024 - 6y - 4y = 102410y=1024 - 10y = 1010y=14-10y = -14y=1.4y = 1.4

  • First: 3(6)4(1)=184=14 eq103(6) - 4(1) = 18 - 4 = 14 \ eq 10
  • Second: 6+2(1)=86 + 2(1) = 8

Step 1: Isolate xx in the second equation: x=82yx = 8 - 2y

Step 2: Substitute into the first equation: 3(82y)4y=143(8 - 2y) - 4y = 14246y4y=1424 - 6y - 4y = 1410y=10-10y = -10y=1y = 1

Step 3: Find xx: x=82(1)=6x = 8 - 2(1) = 6

Solution: (6,1)(6, 1)

Verification: 3(6)4(1)=143(6) - 4(1) = 14 ✓ and 6+2(1)=86 + 2(1) = 8

💡 Strategic Tip: Isolate the variable with coefficient 1 for simpler substitution.

Choice B is incorrect because3(4)4(12)=122=103(4) - 4(\frac{1}{2}) = 12 - 2 = 10...wait that works! But 4+2(12)=5 eq84 + 2(\frac{1}{2}) = 5 \ eq 8.

Choice C is incorrect because2+2(3)=82 + 2(3) = 8 ✓, but 3(2)4(3)=6 eq143(2) - 4(3) = -6 \ eq 14.

Choice D is incorrect because3(8)4(0)=24 eq143(8) - 4(0) = 24 \ eq 14.