Choice A is the correct answer. First, we need to i- 2x+y=2(5)+1=11 ✓
- x−3y=? → 5−3(1)=2
Step 1: Isolate x in the second equation:
x=2+3y
Step 2: Substitute into the first equation:
2(2+3y)+y=114+6y+y=114+7y=117y=7y=1
Step 3: Find x:
x=2+3(1)=5
Solution: (5,1)
Verification: 2(5)+1=11 ✓ and 5−3(1)=2 ✓
💡 Strategic Tip: When neither variable is isolated, choose the variable with coefficient 1 for easier algebra.
Choice B is incorrect because2(4)+3=11 ✓, but 4−3(3)=−5 eq2.
Choice C is incorrect because2(6)+(−1)=11 ✓, but 6−3(−1)=9 eq2.
Choice D is incorrect because2(3)+5=11 ✓, but 3−3(5)=−12 eq2.