6
algebra

Solve by elimination: {6x+2y=206x2y=16\begin{cases} 6x + 2y = 20 \\ 6x - 2y = 16 \end{cases}

A

(2,4)(2, 4)

B

(4,2)(4, -2)

C

(3,1)(3, 1)

D

(5,5)(5, -5)

Correct Answer: C

Choice C is the correct answer. The 2y2y terms are opposites, so we add the equations.

Step 1: Add the equations: (6x+2y)+(6x2y)=20+16(6x + 2y) + (6x - 2y) = 20 + 1612x=3612x = 36x=3x = 3

Step 2: Substitute x=3x = 3 into the first equation: 6(3)+2y=206(3) + 2y = 2018+2y=2018 + 2y = 202y=22y = 2y=1y = 1

Solution: (3,1)(3, 1)

Verification: 6(3)2(1)=182=166(3) - 2(1) = 18 - 2 = 16

💡 Strategic Tip: Opposite coefficients make addition the fastest elimination method.

Choice A is incorrect because6(2)+2(4)=12+8=206(2) + 2(4) = 12 + 8 = 20 ✓, but 6(2)2(4)=128=4 eq166(2) - 2(4) = 12 - 8 = 4 \ eq 16.

Choice B is incorrect because6(4)2(2)=24+4=28 eq166(4) - 2(-2) = 24 + 4 = 28 \ eq 16.

Choice D is incorrect because6(5)+2(5)=3010=206(5) + 2(-5) = 30 - 10 = 20 ✓, but 6(5)2(5)=30+10=40 eq166(5) - 2(-5) = 30 + 10 = 40 \ eq 16.