10
algebra

At a bakery, 2 croissants and 3 muffins cost $11. If each croissant costs $2, what is the cost of one muffin?

A

\2$

B

\2.50$

C

\2.33$

D

\3$

Correct Answer: C

Choice C is the correct answer. Let cc be the cost of a croissant and mm be the cost of a muffin.

Given: c=2c = 2 and 2c+3m=112c + 3m = 11

Step 1: Substitute c=2c = 2: 2(2)+3m=112(2) + 3m = 114+3m=114 + 3m = 11

Step 2: Solve for mm: 3m=73m = 7m=732.33m = \frac{7}{3} \approx 2.33

Solution: One muffin costs approximately $2.332.33.

Verification: 2(2)+3(73)=4+7=112(2) + 3(\frac{7}{3}) = 4 + 7 = 11

💡 Strategic Tip: When one variable is given, substitute immediately to simplify.

Choice A is incorrect because2(2)+3(2)=4+6=10 eq112(2) + 3(2) = 4 + 6 = 10 \ eq 11.

Choice B is incorrect because2(2)+3(2.5)=4+7.5=11.5 eq112(2) + 3(2.5) = 4 + 7.5 = 11.5 \ eq 11.

Choice D is incorrect because2(2)+3(3)=4+9=13 eq112(2) + 3(3) = 4 + 9 = 13 \ eq 11.