7
algebra

Solve by elimination: {3x+2y=163x2y=8\begin{cases} 3x + 2y = 16 \\ 3x - 2y = 8 \end{cases}

A

(3,3.5)(3, 3.5)

B

(5,0.5)(5, 0.5)

C

(4,2)(4, 2)

D

(2,5)(2, 5)

Correct Answer: C

Choice C is the correct answer. The 2y2y terms are opposites, so we add the equations.

Step 1: Add the equations: (3x+2y)+(3x2y)=16+8(3x + 2y) + (3x - 2y) = 16 + 86x=246x = 24x=4x = 4

Step 2: Substitute x=4x = 4 into the first equation: 3(4)+2y=163(4) + 2y = 1612+2y=1612 + 2y = 162y=42y = 4y=2y = 2

Solution: (4,2)(4, 2)

Verification: 3(4)2(2)=124=83(4) - 2(2) = 12 - 4 = 8

💡 Strategic Tip: Opposite coefficients signal that addition is the right move.

Choice A is incorrect because3(3)+2(3.5)=9+7=163(3) + 2(3.5) = 9 + 7 = 16 ✓, but 3(3)2(3.5)=97=2 eq83(3) - 2(3.5) = 9 - 7 = 2 \ eq 8.

Choice B is incorrect because3(5)2(0.5)=151=14 eq83(5) - 2(0.5) = 15 - 1 = 14 \ eq 8.

Choice D is incorrect because3(2)+2(5)=6+10=163(2) + 2(5) = 6 + 10 = 16 ✓, but 3(2)2(5)=610=4 eq83(2) - 2(5) = 6 - 10 = -4 \ eq 8.