Choice A is the correct answer. Linear programming.

1. Constraints:
   • Weight: $50A + 40B \leq 2000 \rightarrow 5A + 4B \leq 200$
   • Volume: $10A + 20B \leq 500 \rightarrow A + 2B \leq 50$
2. Vertices:
   • Intersection: $2(A + 2B = 50) \rightarrow 2A + 4B = 100$. Subtract from weight eq: $(5A+4B) - (2A+4B) = 200 - 100 \rightarrow 3A = 100 \rightarrow A = 33.3$. $B = 8.3$. (Integer constraints might apply, but let's assume continuous for estimation or check corners).
   • Corner 1 (Max A): $B=0, A=40$ (Weight limit). Rev: $20(40) = 800$.
   • Corner 2 (Max B): $A=0, B=25$ (Volume limit). Rev: $25(25) = 625$.
   • Intersection approx $(33.3, 8.3)$: $20(33.3) + 25(8.3) \approx 666 + 207 = 873$.
   • Wait, let me re-check Corner 1. $A=40, B=0$. Vol: $10(40)=400 \leq 500$. OK. Rev: 800.
   • Let me check $A=50, B=0$ (Volume limit). Weight: $50(50)=2500 > 2000$. Fail.
   • Is there a better point? Let's check the objective function slope vs constraint slopes.
   • Slope Rev: $-20/25 = -0.8$.
   • Slope Weight: $-5/4 = -1.25$.
   • Slope Vol: $-1/2 = -0.5$.
   • The revenue slope is between the constraint slopes. The max should be at the intersection.
   • Intersection: $A=100/3, B=25/3$. Rev: $20(100/3) + 25(25/3) = (2000+625)/3 = 2625/3 = 875$.

Wait, none of the options match 875. Let me re-read. Maybe I missed a constraint or simple calculation. Let's check Option A: 1000. Is it possible? If $A=50$, Rev=1000. Weight: $50(50)=2500$ (Fail). If $B=40$, Rev=1000. Weight: $40(40)=1600$ (OK). Vol: $20(40)=800$ (Fail).

Let me re-read the problem. Maybe I copied numbers wrong. Truck: 2000 lbs, 500 cu ft. A: 50 lbs, 10 cu ft. $20. B: 40 lbs, 20 cu ft.$25.

Let's check $A=20, B=20$. W: $1000+800=1800$. V: $200+400=600$ (Fail). Let's check $A=30, B=10$. W: $1500+400=1900$. V: $300+200=500$. OK. Rev: $600+250=850$. Let's check $A=40, B=0$. Rev 800. Let's check $A=0, B=25$. Rev 625.

Maybe the options are for a different problem or I made a mistake in generation. Let me adjust the problem to fit an option, or adjust the option to fit the math. Let's change Revenue for A to $30. If Rev A =$30:

• Intersection: $30(33.3) + 25(8.3) = 1000 + 208 = 1208$.
• Corner A=40: $30(40) = 1200$.

Let's change the problem to match Option A (1000) simply. Let's say Maximize $P = 20A + 20B$.

• Intersection: $20(33.3+8.3) = 20(41.6) = 833$.
• Corner A=40: 800.

Let's try to find a scenario where 1000 is the answer. Maybe capacity is 2500 lbs? If 2500 lbs, 500 cu ft. Max A (Vol limit): $A=50$. W: $2500$. OK. Rev: $20(50) = 1000$. Max B (Vol limit): $B=25$. Rev: 625. Intersection: $5A+4B=250, A+2B=50$. $2A+4B=100$. $3A=150, A=50, B=0$. So if capacity is 2500 lbs, max is at A=50, Rev=1000.

ADJUSTMENT: I will change the Truck Capacity to 2500 lbs in the prompt.

Choice A is correct (with 2500 lbs).