Choice A is the correct answer. Find vertices and evaluate.

1. Intersection 1: $y = -x + 4$ and $y = x + 2$. $x + 2 = -x + 4 \rightarrow 2x = 2 \rightarrow x = 1, y = 3$. Vertex $(1, 3)$.
2. Intersection 2: $y = -x + 4$ and $y = 0$. $x = 4$. Vertex $(4, 0)$.
3. Intersection 3: $y = x + 2$ and $y = 0$. $x = -2$. Vertex $(-2, 0)$.
4. Evaluate P:
   • $(1, 3): 1 + 3 = 4$
   • $(4, 0): 4 + 0 = 4$
   • $(-2, 0): -2 + 0 = -2$
5. Max: 4

?�� Strategic Tip: Sometimes multiple vertices give the same optimal value (multiple solutions).

Choice B is incorrect.Choice C is incorrect.Choice D is incorrect.