Choice A is the correct answer. Split into two separate compound inequalities.

1. Positive Case: $4 < x + 2 < 8 \rightarrow 2 < x < 6$
2. Negative Case: $4 < -(x + 2) < 8 \rightarrow 4 < -x - 2 < 8$
   • Add 2: $6 < -x < 10$
   • Multiply by -1: $-6 > x > -10$ (Reverse!)
   • Rewrite: $-10 < x < -6$
3. Combine: $2 < x < 6$ or $-10 < x < -6$

?�� Strategic Tip: This describes two intervals symmetric around the center (-2).

Choice B is incorrect because it misses the negative interval. Choice C is incorrect because it misses the positive interval. Choice D is incorrect because it represents the "hole" in the middle.