2
algebra

Solve: 3x27|3x - 2| \leq 7

A

53x3-\frac{5}{3} \leq x \leq 3

B

3x3-3 \leq x \leq 3

C

x3x \leq 3

D

x53x \leq -\frac{5}{3} or x3x \geq 3

Correct Answer: A

Choice A is the correct answer. "Less thAND" \rightarrow Compound inequality.

  1. Setup: 73x27-7 \leq 3x - 2 \leq 7
  2. Add 2: 53x9-5 \leq 3x \leq 9
  3. Divide by 3: 53x3-\frac{5}{3} \leq x \leq 3

?�� Strategic Tip: Add the constant to both sides of the compound inequality.

Choice B is incorrect because it solves the left side incorrectly. Choice C is incorrect because it misses the lower bound. Choice D is incorrect because it treats it as an "or" inequality.