Choice A is the correct answer. Absolute value inequalities with $<$ become compound "and" inequalities.

1. Setup: $-5 < x - 3 < 5$
2. Add 3: $-5 + 3 < x < 5 + 3$
3. Simplify: $-2 < x < 8$

?�� Strategic Tip:$|A| < b$ becomes $-b < A < b$. Think "Less thAND" (Less than = And).

Choice B is incorrect because it ignores the lower bound. Choice C is incorrect because it models $|x-3| > 5$ ("GreatOR" = Or). Choice D is incorrect because it solves incorrectly.