1
algebra

Solve: 3<2x+17-3 < 2x + 1 \leq 7

A

2<x3-2 < x \leq 3

B

2x<3-2 \leq x < 3

C

1<x4-1 < x \leq 4

D

1x<4-1 \leq x < 4

Correct Answer: A

Choice A is the correct answer. Solve the compound inequality by performing operations on all three parts simultaneously.

  1. Subtract 1: 31<2x+1171-3 - 1 < 2x + 1 - 1 \leq 7 - 1, giving 4<2x6-4 < 2x \leq 6
  2. Divide by 2: 42<2x262\frac{-4}{2} < \frac{2x}{2} \leq \frac{6}{2}
  3. Simplify: 2<x3-2 < x \leq 3

?�� Strategic Tip: Whatever you do to the middle, you must do to the left and right sides.

Choice B is incorrect because it swaps the strict (<<) and inclusive (\leq) inequalities. Choice C is incorrect because it might result from adding 1 instead of subtracting. Choice D is incorrect because it combines wrong values and wrong signs.