2
algebra

Solve: 8x+124x+288x + 12 \leq 4x + 28

A

x4x \leq 4

B

x4x \geq 4

C

x10x \leq 10

D

x10x \geq 10

Correct Answer: A

Choice A is the correct answer. Inequalities with variables on both sides require combining like terms.

  1. Subtract 4x: 8x4x+124x4x+288x - 4x + 12 \leq 4x - 4x + 28, giving 4x+12284x + 12 \leq 28
  2. Subtract 12: 4x+121228124x + 12 - 12 \leq 28 - 12, giving 4x164x \leq 16
  3. Divide by 4: x4x \leq 4

?�� Strategic Tip: To solve inequalities with variables on both sides, move all variable terms to one side and all constants to the other.

Choice B is incorrect because it reverses the inequality without mathematical justification. Choice C is incorrect because it might come from adding 12 and 28 to get 40, then dividing by 4. Choice D is incorrect because it combines wrong value (10) with wrong direction (\geq).