8
algebra

If 3x+2113x + 2 \geq 11, what is the smallest integer value of xx?

A

33

B

44

C

22

D

55

Correct Answer: A

Choice A is the correct answer. Solve and find the minimum integer.

  1. Subtract 2: 3x93x \geq 9
  2. Divide by 3: x3x \geq 3
  3. Smallest integer: x=3x = 3

💡 Strategic Tip: For \geq, the boundary value is included.

Choice B is incorrect because 4 is not the smallest. Choice C is incorrect because2<32 < 3 doesn't satisfy the inequality. Choice D is incorrect because 5 is not the smallest.