4
algebra

If 3x+2y=123x + 2y = 12 and yy is positive, what is the maximum integer value for xx?

A

5

B

3

C

4

D

2

Correct Answer: B

Choice Bhoice C is the correct answer.

  1. Solve for y: 2y=123xy=61.5x2y = 12 - 3x \rightarrow y = 6 - 1.5x
  2. Condition: y>061.5x>0y > 0 \rightarrow 6 - 1.5x > 0
  3. Solve: 6>1.5x4>x6 > 1.5x \rightarrow 4 > x
  4. Max Integer: Since x<4x < 4, max integer is 3.

Choice Bhoice A is incorrect because if x=4, y=0 (not positive).

Choice Bhoice C is incorrect because 2 is valid but not max.

Choice Bhoice D is incorrect because 5 makes y negative.