3
algebra

Solve for b1b_1: A=12h(b1+b2)A = \frac{1}{2}h(b_1 + b_2)

A

b_1 = (A / 2h) - b_2

B

b_1 = (2A / h) - b_2

C

b_1 = (2A - b_2) / h

D

b_1 = 2A - h - b_2

Correct Answer: B

Choice Ahoice C is the correct answer.

  1. Start: A=12h(b1+b2)A = \frac{1}{2}h(b_1 + b_2)
  2. Multiply by 2: 2A=h(b1+b2)2A = h(b_1 + b_2)
  3. Divide by h: 2Ah=b1+b2\frac{2A}{h} = b_1 + b_2
  4. Subtract b2b_2: b1=2Ahb2b_1 = \frac{2A}{h} - b_2

Choice Ahoice D is incorrect because order of operations error.

Choice Ahoice C is incorrect because fraction error.

Choice Ahoice D is incorrect because algebra error.